Physics - Geometrical Optics Question with Solution | TestHub

Given, $A=30^{\circ },\mu =1.5$ and $i_1=0^{\circ }$ Since, $i_0$, therefore, $r_1$ is also equal to $0^{\circ }$ Further, since, $r_1+r_2=A$ $\therefore r_2=A=30^{\circ }$ Using Snell's Law, $\mu =\frac{\sin i_2}{\sin r_2}$ $\Rightarrow 1.5=\frac{\sin i_2}{\sin 30^{\circ }}$ or $i_2=1.5\sin 30^{\circ }=1.5\times \frac{1}{2}=0.75$ or $i_2=1.5\sin 30^{\circ }=1.5\times \frac{1}{2}=0.75$ Now, the deviation, $\delta =\left(i_1+i_2\right)-A=(0+48.6)-30=18.6^{\circ }$