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PhysicsGeometrical OpticsTIR/Prism and DispersionEasy2 minPYQ_2020
PhysicsEasynumerical

A prism of angleA=1°μ=1.5. A good estimate for the minimum angle of deviation (in degrees) is close toN10.Value ofNis

Answer:
5.00
Solution:

Given,

Angle of prism, A=1°

Refractive index of prism, μ=1.5

For this prism, minimum angle of deviation is given by

δ=(μ-1)A

δ=(1.5-1)×1°=12=510=N10

N=5

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion
2mℹ️ Source: PYQ_2020

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