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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minPYQ_2018

PhysicsMediumsingle choice

Focal length of convex lens is $100 cm$ and focal length of concave lens is $8 cm$ . Find the magnification of the given combination of lens if object is placed at point $O$ .

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Answer:

Solution:

For first lens $m_{1} = \frac{v}{u} = \frac{f}{u + f} = \frac{100}{- 50 + 100} = 2$ Image distance $v = 2 u = 2 \times (- 50) = - 100 cm$ For second lens Now $u = - 190 cm, f = - 8 cm, m_{2} =$ ? $m_{2} = \frac{v}{u} = \frac{f}{u + f} = \frac{- 8}{- 190 - 8} = 0.04$ Net magnification $= m_{1} m_{2} = 0.08$

Stream:AIIMSSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2018

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