Two parallel beams of light pass through an isosceles prism of refractive index 1.4 as shown in the figure. The angle between the two emergent rays is $18 X^{o}$ calculate X. $[sin 3 5^{\circ} = 0.57, sin^{- 1} (0.798) = 5 3^{\circ}]$

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r = 3 5 ∘ i = sin − 1 ( 1.4 sin 3 5 ∘ ) = 5 3 ∘ Deviation of each emergent ray is 18 degrees. Angle between the two emergent rays = 36 degrees = 18X degrees. X = 2

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