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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2020

PhysicsEasysingle choice

A student plots a graph between the inverse of magnification $\frac{1}{m}$ produced by a thin convex lens and the object position $u$ as shown in the figure. The focal length of the lens used, was

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Answer:

Solution:

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{u}{v} - 1 = \frac{u}{f}$

$\frac{u}{v} = \frac{u}{f} + 1$

$\frac{1}{m} = \frac{u}{f} + 1$

$slope = \frac{1}{f}$

$\frac{1}{f} = \frac{b}{c}$

$f = \frac{c}{b}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2020

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