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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is

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Answer:

Solution:

Excess pressure inside a spherical drop of water

$p = \frac{2 T}{R}$

$G i v e n, p_{1} = 4 p_{2}$

$\frac{2 T}{R_{1}} = 4 \times \frac{2 T}{R_{2}}$

$o r R_{2} = 4 R_{1}$

$N o w, \frac{m_{1}}{m_{2}} = \frac{4 π R_{1}^{3} d_{1}}{4 π R_{2}^{3} d_{2}}$

$o r \frac{m_{1}}{m_{2}} = \frac{R_{1}^{3}}{R_{2}^{3}}$

$\frac{m_{1}}{m_{2}} = \frac{1}{64}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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