A massless cylindrical container of base area $100 cm^{2}$ contains a solid of volume $V = 500 cm^{3}$ and specific gravity 2 . The container is floating in another cylindrical container of base area $1000 c m^{2}$ . If the solid is shifted from container 1 to 2 , the height through which the liquid level decreases by

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Let v i ​ is initial immersed volume of small container. 500 ( 2 ) g = v i ​ ( 1 ) g ⇒ v i ​ = 1000 c m 3 . This is initial volume of liquid displaced. Final volume of liquid displaced will be V = 500 cm 3 only. Decrease in liquid level h = A V i ​ − V ​ = 1000 100 − 500 ​ = 2 1 ​ cm

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JEE Advanced (2028)