Physics - Fluid Question with Solution | TestHub

For steady ideal flow, Bernoulli applies along each streamline.
The narrowing tube (1) has a larger speed at B than at A:
$$v_B>v_A$$
$$P_B-P_A=\rho gh+\frac{1}{2}\rho (v_A^2-v_B^2)$$
$$P_B-P_A<\rho gh$$
The uniform tube (2) has equal speeds at C and D:
$$P_D-P_C=\rho gh$$
$$P_B-P_A<P_D-P_C$$
Thus B and D are correct.