Two resistors are measured as R 1 = ( 5.0 ± 0.2 ) Ω and R 2 = ( 10.0 ± 0.1 ) Ω . Find their nominal parallel resistance in ohms to two significant figures.

R p = R 1 + R 2 R 1 R 2 = 15 5 ( 10 ) = 3.333 … Ω → 3.3 Ω .

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PhysicsErrorMiscellaneousMedium2 minQB

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Two resistors are measured as $R_{1} = (5.0 \pm 0.2) Ω$ and $R_{2} = (10.0 \pm 0.1) Ω$ . Find their nominal parallel resistance in ohms to two significant figures.

Answer:

3.30

Solution:

$R_{p} = \frac{R _{1} R _{2}}{R _{1} + R _{2}} = \frac{5 ( 10 )}{15} = 3.333 \dots Ω \to 3.3 Ω$ .

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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