If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smallest reading of main scale is 0 . 5 mm the Vernier constant of travelling microscope is:

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TestHub · Accepted Answer

The number of divisions on the vernier scale $= 50$
Main scale division $(MSD) = 0.5 mm$
As, $50$ divisions on the vernier scale coincide with $49$ divisions on the main scale,
$VSD = \frac{49}{50} MSD$
The minimum inaccuracy in the measurement of distance by a vernier scale,
$=$ Least count of the vernier scale
$= 1 MSD - 1 VSD$
$= 1 MSD - \frac{49}{50} MSD$
$= \frac{1}{50} MSD = \frac{1}{50} \times 0.5 mm$
$= 0.01 mm$ .

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