The vernier shown has zero error. It has $10$ vernier divisions equal to $9$ main scale divisions, and one main scale division is $1 mm$ . A rod's observed reading is $5.4 mm$ . For an error-free instrument, which vernier division would coincide?

Question

Reconstructed diagram: source figure lacked vernier ticks. Scale positions inferred from printed zero error and 10 VSD = 9 MSD.

TestHub · Accepted Answer

True length = 5.4 + 0.7 = 6.1 mm . Main scale reading = 6 mm ; residual = 0.1 mm . Coincidence = 0.1 0.1 ​ = 1 .

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