Start Free Mock LoginAlready registered? Login here

Physics - Error Question with Solution | TestHub

PhysicsErrorMiscellaneousMedium2 minQB

PhysicsMediuminteger

In the formula $K = Ae^{- \frac{E _{a}}{RT}}, A, R, E_{a}$ are kept constant. K is recorded for different values of absolute temperature T. The ratio of small fractional error in K, in the case when fluctuation of 1% in T exists at 27°C to the case when the same fluctuation of $1%$ in T exists at $12 7^{\circ} C$ is given by $\frac{x}{6}$ . Then $x =$ $____$

Answer:

Solution:

$K = A e^{- E_{a} / RT} \Rightarrow ln K = ln A - \frac{E _{a}}{RT} \Rightarrow \frac{d K}{K} = \frac{E _{a}}{RT} \frac{d T}{T}$

With $\frac{Δ T}{T} = 0.01$ at both temperatures: $\frac{( Δ K / K ) _{A}}{( Δ K / K ) _{B}} = \frac{T _{B}}{T _{A}} = \frac{400}{300} = \frac{4}{3} = \frac{x}{6}$

$x = 8$

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...