Physics - Error Question with Solution | TestHub

PhysicsErrorMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

A particle is projected with velocityv0alongx-axis. The deceleration on the particle is proportional to the square of the distance from the origini.e. a=-x2. The distance at which particle stops is -

Options:

Answer:
D
Solution:

Given initial velocity = v0

final velocity = 0

a = - x 2

now we know that a = dv dt and v = dx dt

thus a = dv dt = dv dt · dx dx = vdv dx

vdv dx = - x 2

vdv = - x 2 dx

integrating we get

∫ v 0 0 vdv = ∫ 0 x - x 2 dx

v 2 2 v 0 0 = - x 3 3 0 x

- v 0 2 2 = - x 3 3     ⇒     x = 3 v 0 2 2 1 3

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ErrorSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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