Two full turns of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50 . Further, it is found that the screw gauge

Question

Two full turns of the circular scale of a screw gauge cover a distance of $1 mm$ on its main scale. The total number of divisions on the circular scale is 50 . Further, it is found that the screw gauge has a zero error of $- 0.03 mm$ while measuring the diameter of a thin wire, a student notes the main scale reading of $3 mm$ and the number of circular scale divisions in line with the main scale as 35 . The diameter of the wire is

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Answer:

D

Solution:

Diameter $=$ M.S.R. $+$ C.S.R $\times$ L.C. $+$ Z.E. $= 3 + 35 \times (0.5/50) + 0.03 = 3.38 mm$

TestHub · Accepted Answer

Diameter = M.S.R. + C.S.R × L.C. + Z.E. = 3 + 35 × ( 0.5/50 ) + 0.03 = 3.38 mm

Physics - Practical physics Question with Solution | TestHub

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