An inductor coil and a capacitor and a resistance of 5 Ω are connected in series to an a.c. source of rms voltage 30 V . When the frequency of the source is varied, a maximum r.m.s. current of 5 A is

Question

An inductor coil and a capacitor and a resistance of $5 Ω$ are connected in series to an a.c. source of rms voltage $30 V$ . When the frequency of the source is varied, a maximum r.m.s. current of $5 A$ is observed. If this inductor is connected in parallel with a resistance $5 Ω$ to a battery of emf $25 V$ and internal resistance $2.0 Ω$ , the current drawn from the battery is

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Answer:

A

Solution:

Let resistance of inductor be $μ$

$I_{max} = \frac{30}{5 + μ} = 5 \Rightarrow μ = 1 Ω$

Now, $I = \frac{25}{\frac{5}{6} + 2}$

$= \frac{150}{17} A$

TestHub · Accepted Answer

Let resistance of inductor be μ I max = 3 0 5 + μ = 5 ⇒ μ = 1 Ω Now, I = 2 5 5 6 + 2 = 1 5 0 1 7 A

Physics - EMI/AC Question with Solution | TestHub

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