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PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2014

PhysicsEasysingle choice

A coil of resistance $10Ω$ and an inductance $5 H$ is connected to a $100 V$ battery. The energy stored in the coil is

Answer:

Solution:

Current $I = \frac{V}{R} = \frac{100}{10} = 10 A$ Energy, $E = \frac{1}{2} LI^{2}$ $= \frac{1}{2} \times 5 \times (10)^{2} = 250 J$

Stream:VITEEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2014

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