The given figure shows an inductor and resistance fixed on a conducting wire. A movable conducting wire PQ starts moving on the fixed rails from $t = 0$ with constant velocity $1 m / s$ . The work done (in J) by the external force on the wire PQ in 2 seconds is :

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E = B ℓ v = 2 × 2 × 1 = 4 V L d t d i ​ = 4 ⇒ 2 d t d i ​ = 4 ⇒ i L ​ = 2 t = 4 A at t = 2 s i R ​ = 2 4 ​ = 2 A W = 2 1 ​ L i L 2 ​ + i R 2 ​ Rt = 2 1 ​ × 2 × 16 + 4 × 2 × 2 = 16 + 16 W = 32 J Answer: 32.00

Physics - EMI/AC Question with Solution | TestHub

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