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PhysicsEMI/ACAC current and voltageMedium2 minPYQ_2021
PhysicsMediumnumerical

The alternating current is given by, i=42sin2πTt+10 A. The R.M.S. value of this current is __________ A.

Answer:
11.00
Solution:

The given function of current is, i=42sin2πTt+10 A

It means,  i2=42sin22πtT+100+2042sin2πtT

i2=422+100

RMS value of the current is, irms=i2=121=11 A

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:AC current and voltage
2mℹ️ Source: PYQ_2021

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