A LCR circuit is at resonance for a capacitor C , inductance L and resistance R . Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be no

Question

A LCR circuit is at resonance for a capacitor C , inductance L and resistance R . Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:

TestHub · Accepted Answer

In resonance Z = R ​ I = R V ​ R → halved ⇒ I → 2 I ​ I becomes doubled.

Physics - EMI/AC Question with Solution | TestHub

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