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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2009

PhysicsEasysingle choice

A coil of wire of a certain radius has 100 turns and a self inductance of $15 mH$ . The self inductance of a second similar coil of 500 turns will be

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Solution:

Inductance of a coil is given by $L = \frac{1}{2} μ_{0} π N^{2} R \Rightarrow \frac{L _{2}}{L _{1}} = \frac{N _{2}^{2}}{N _{1}^{2}} ∴ L_{2} = L_{1} \frac{N _{2}^{2}}{N _{1}^{2}} = (\frac{500}{100})^{2} 15 mH = 375 mH$

Stream:AIIMSSubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2009

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