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PhysicsEMI/ACFaraday law/Lenz lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A conducting circular loop is placed in a uniform magnetic field $0.04 T$ with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at $2 mm s^{- 1}$ . The induced emf in the loop, when the radius is $2 cm$ , is

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Answer:

Solution:

$ϕ = BA cos θ = B (π r^{2}) cos 0^{\circ} = B π r^{2}$

$|ε| = \frac{d ϕ}{dt} = B π (2 r) \frac{dr}{dt}$

$= 0.04 \times π \times (2 \times 2 \times 1 0^{- 2}) \times 2 \times 1 0^{- 3}$

$= 3.2 π \times 1 0^{- 6} V = 3.2 π μ V$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: PYQ_2020

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