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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSelf and mutual inductorMedium2 minPYQ_2022

PhysicsMediumsingle choice

In an inductor of self-inductance $L = 2 mH$ , current changes with time according to relation $i = t^{2} e^{- t}$ . At what time emf is zero?

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Answer:

Solution:

$L = 2 mH, i = t^{2} e^{- t}$ $E = - L \frac{di}{dt} = - L [- t^{2} e^{- t} + 2 te e^{- t}]$ when $E = 0$ , $- e^{- t} t^{2} + 2 te - t = 0 or, 2 t e^{- t} = e^{- t} t^{2} \Rightarrow t = 2 sec .$

Stream:VITEEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2022

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