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PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2020

PhysicsEasynumerical

Two coils are fixed in space at some distance from each other such that there is a flux linkage between them. When coil $1$ has no current and the current in the coil $2$ increases at the rate $15.0$ $A s^{- 1}$ , the emf in the coil $1$ is $25.0 mV$ . When coil $2$ has a current of $3.6 A$ , the flux linkage in coil $2$ (in $mWb$ ) is

Answer:

6.00

Solution:

As $e = M \frac{d i}{d t}$

$∴ M = \frac{e}{d i / d t} = \frac{25 \times 10^{- 3}}{15.0} = 1.67 \times 10^{- 3} H$

As $ϕ = M i$

$∴ ϕ = 1.67 \times 10^{- 3} \times 3.6 = 6 \times 10^{- 3}$ Wb

$= 6 mWb$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2020

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