Physics - EMI/AC Question with Solution | TestHub

The instantaneous emf is given by $E=E_0\cos (\omega t)$.

Given $E_0=10$ V and frequency $f=50$ Hz.

Angular frequency $\omega =2\pi f=2\pi (50)=100\pi$ rad/s.

At $t=1/600$ s:

$E=10\cos (100\pi \times \frac{1}{600})=10\cos (\frac{\pi }{6})$

$E=10\times \frac{\sqrt{3}}{2}=5\sqrt{3}$ V.