Physics - EMI/AC Question with Solution | TestHub

At$\mathrm{t}=0$,$\mathrm{L}$behaves as open circuit and at$\mathrm{t}=\mathrm{\infty }$as short circuit.
So at$\mathrm{t}=0, \mathrm{i}=\frac{10}{10}=1 \mathrm{A} [\because {\mathrm{R}}_{\mathrm{eq}}=10 \mathrm{\Omega }]$
and at$\mathrm{t}=\mathrm{\infty }, \mathrm{i}=\frac{10}{\left(\frac{10}{3}\right)}=3 \mathrm{A} [\because {\mathrm{R}}_{\mathrm{eq}}=\frac{10}{3} \mathrm{\Omega }]$