Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACAC current and voltageMedium2 minPYQ_2011

PhysicsMediumsingle choice

The rms value of potential difference $V$ shown in the figure is
NEET 2011 (Mains)

Options:

Answer:

Solution:

$V_{rms} = [\frac{1}{T} \int_{0}^{T /2} V_{0}^{2} d t]^{1/2}$ $V_{rms} V_{mms} = [\frac{V _{0}^{2}}{T} [t]_{0}^{T /2}]^{1/2} = [\frac{V _{0}^{2}}{T} (\frac{T}{2})]^{1/2} = [\frac{V _{0}^{2}}{2}]^{1/2} = \frac{V _{0}}{2}$

Stream:NEETSubject:PhysicsTopic:EMI/ACSubtopic:AC current and voltage

⏱ 2mℹ️ Source: PYQ_2011

Doubts & Discussion

Loading discussions...