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PhysicsEMI/ACSeries AC CircuitsHard2 minPYQ_2010

PhysicsHardsingle choice

An AM wave has $1800 W$ of total power content. For $100%$ modulation the carrier should have power content equal to

Answer:

Solution:

Total power $P_{t} = P_{c} [1 + \frac{m a ^{2}}{2}] ∵ m a^{2} = 1$ $∴ 1800 = P_{c} [1 + \frac{1}{2}] \Rightarrow P_{c} = 1200 W$

Stream:VITEEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2010

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