Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

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In a series $LCR$ circuit, the voltage across the resistor, capacitor and inductor is $10 V$ each. If the capacitor is short-circuited, the voltage across the inductor will be

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Answer:

Solution:

Here, $R = X_{L} = X_{C}$ , because voltage across them is the same.

When the capacitor is short circuited,

$I = \frac{10}{{(R^{2} + X_{L}^{2})}^{\frac{1}{2}}} = \frac{10}{\sqrt{2} R}$

Hence, potential drop across inductor $= {IX}_{L} = IR = \frac{10}{\sqrt{2}} V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

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