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PhysicsEMI/ACAC current and voltageMedium2 minPYQ_2019
PhysicsMediumsingle choice

An alternating voltageV(t)=220sin100πtvolt is applied to a purely resistive load of50 Ω. The time taken for the current to rise from half of the peak value to the peak value is:

Options:

Answer:
D
Solution:

i=VR=22050sin100πt
i=imaxsin100πt
For i=imax2: 
imax2=imaxsin100πt
sin100πt=12 100πt=π6
t=1600  s
For i=imax:
 imax=imaxsin100πt
sin100πt=1 100πt=π2
t=1200 s

so time for  imax2 to imax is 
t(imax)-timax2=1200-1600=1300=3.33 ms

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:AC current and voltage
2mℹ️ Source: PYQ_2019

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