Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

PhysicsEasysingle choice

The figure below shows a battery of emf $ε$ connected to an inductor $L$ and a resistance $R$ in series. If the switch is closed at $t = 0$ , then the total charge that flows from the battery in one time constant of the circuit is

Options:

Answer:

Solution:

$q = \int_{0}^{τ} \frac{ε}{R} (1 - e^{- t / τ}) d t$

$q = \frac{ε}{R} {[t - \frac{e^{- t / τ}}{\frac{- 1}{τ}}]}_{0}^{τ} = \frac{ε}{R} [τ + τ e^{- 1} - τ]$
$q = \frac{ε}{R} \times \frac{1}{e} \times \frac{L}{R} = \frac{ε L}{R^{2} e}$

Stream:NTA_ABHYASSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...