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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACTransformerEasy2 minPYQ_2020

PhysicsEasysingle choice

A transformer with efficiency $80 %$ works at $4 kW$ and $100 V$ . If the secondary voltage is $200 V,$ then the primary and secondary currents are respectively

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Answer:

Solution:

Here, $η = 80 %$

$P_{i} = 4 kW = 4000 W$

$V_{p} = 100 V, V_{s} = 200 V$

$I_{p} = \frac{P_{i}}{V_{p}} = \frac{4000}{100} = 40 A$

$η = \frac{V_{s} I_{s}}{V_{p} I_{p}}; \frac{80}{100} = \frac{200 I_{s}}{4000} = \frac{I_{s}}{20}$

or $I_{s} = \frac{20 \times 80}{100} = 16 A$

Subject:PhysicsTopic:EMI/ACSubtopic:Transformer

⏱ 2mℹ️ Source: PYQ_2020

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