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PhysicsEMI/ACMotional & Rotational EMFMedium2 minPYQ_2020
PhysicsMediumsingle choice

A simple pendulum with a bob of mass m and a conducting wire of length L, swings under gravity with an angular amplitudeθ. If the horizontal component of the earth's magnetic field perpendicular to the plane of motion of the pendulum isB, then the maximum emf induced across the pendulum is

Options:

Answer:
A
Solution:

h=L-L cos θ

   h=L(1-cosθ)...(i)
using energy conservation ΔKE=ΔPE
12mv2=mgh=mgL(1cosθ)
v=2g L2 sin2θ2
     v=2gL sinθ2
Thus, maximum potential difference
Vmax=BvL
=B×2gLsinθ2L
=2BL sinθ2gL1/2

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Motional & Rotational EMF
2mℹ️ Source: PYQ_2020

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