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PhysicsEMI/ACMotional & Rotational EMFEasy2 minPYQ_2020

PhysicsEasysingle choice

A copper disc of the radius $0.1 m$ is rotated about its centre with $ω = 20$ revolutions per second in a uniform magnetic field of $0.1 T$ with its plane perpendicular to the field. The emf induced across the radius of the disc is

Options:

Answer:

Solution:

$ε = \frac{B ω R^{2}}{2}$

$= \frac{0.1 \times (2 π \times 20) {(0.1)}^{2}}{2}$

$= 20 π \times 1 0^{- 3} V$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Motional & Rotational EMF

⏱ 2mℹ️ Source: PYQ_2020

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