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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2019

PhysicsEasysingle choice

In LCR series circuit, source voltage is $120 V$ and voltage across inductor $50 V$ . If voltage drop across resistance is $40 V$ , then determine voltage in capacitor.

Options:

Answer:

Solution:

$12 0^{2} = 4 0^{2} + (V_{C} - 50)^{2} V_{C} = 408 + 50 = 10 (5 + 82) V$

Stream:AIIMSSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2019

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