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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsMedium2 minPYQ_2006

PhysicsMediumsingle choice

A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in $0.5$ second. The magnetic flux between the pole pieces is known to be $8 \times 1 0^{- 4} Wb$ . The emf induced in the wire is

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Solution:

Induced emf $e = \frac{- d ϕ}{dt}$ . Assuming, small change in flux $d ϕ = 8 \times 1 0^{- 4} Wb$ change in time $dt = 0.5 s$ $∣ e ∣ = \frac{8 \times 1 0 ^{- 4}}{0.5} = \frac{80 \times 1 0 ^{- 4}}{5} = 16 \times 1 0^{- 4} = 1.6 \times 1 0^{- 3} V = 1.6 mV$

Stream:VITEEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2006

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