Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2025

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An electric bulb rated as $100 W - 220 V$ is connected to an ac source of rms voltage 220 V. The peak value of current through the bulb is :

Answer:

Solution:

$P = v_{rms} i_{rms} i_{rms} = \frac{100}{220} i_{0} = 2 i_{rms} = 0.64 A$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2025

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