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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACFaraday law/Lenz lawEasy2 minPYQ_2018

PhysicsEasysingle choice

A circular ring of diameter $20 cm$ has a resistance of $0.01Ω$ . The charge that will flow through the ring if it is turned from a position perpendicular to a uniform magnetic field of $2.0 T$ to a position parallel to the field is about

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Answer:

Solution:

As $q = \frac{- d ϕ}{R} = \frac{B A ( cos 0 ^{\circ} - cos 9 0 ^{\circ} )}{R} = \frac{B π r ^{2} ( 1 - 0 )}{R} = \frac{B π r ^{2}}{R} = \frac{2 \times 3.14 \times ( 1 0 ^{- 1} ) ^{2}}{0.01} = 6.28 C ≃ 6.3 C$

Stream:AIIMSSubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: PYQ_2018

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