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PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2010

PhysicsEasysingle choice

An AC voltage source of variable angular frequency $ω$ and fixed amplitude $V_{0}$ is connected in series with a capacitance $C$ and an electric bulb of resistance $R$ (inductance zero). When $ω$ is increased

Options:

Answer:

Solution:

$Z = R^{2} + X_{C}^{2} : I_{rms} = \frac{V _{rms}}{Z} : P = I_{rms}^{2} R$ where, $X_{C} = \frac{1}{ω C}$ As $ω$ is increased, $X_{C}$ will decrease or $Z$ will decrease. Hence $I_{mms}$ or $P$ will increase. Therefore, bulb glows brighter. Hence the correct option is (b).

Stream:JEE_ADVSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2010

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