A series LCR circuit is designed to resonate at an angular frequency ω 0 = 1 0 5 r a d s − 1 . The circuit draws 16 W power from 120 V source at resonance. The value of resistance R in the circuit i

Question

A series LCR circuit is designed to resonate at an angular frequency $ω_{0} = 1 0^{5} r a d s^{- 1} .$ The circuit draws $16 W$ power from $120 V$ source at resonance. The value of resistance $R$ in the circuit is ________ $Ω.$

Answer:

900.00

Solution:

At resonance

$P = \frac{V ^{2}}{R}$

$R = \frac{V ^{2}}{P} = \frac{( 120 ) ^{2}}{16}$

$= 900Ω$

TestHub · Accepted Answer

At resonance P = R V 2 ​ R = P V 2 ​ = 16 ( 120 ) 2 ​ = 900Ω

Physics - EMI/AC Question with Solution | TestHub

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