The angular frequency of the damped oscillator is given by, ω = ( m k − 4 m 2 r 2 ) where k is the spring constant, m is the mass of the oscillator and r is the damping constant. If the ratio mk

Question

The angular frequency of the damped oscillator is given by, $ω = (\frac{k}{m} - \frac{r ^{2}}{4 m ^{2}})$ where $k$ is the spring constant, $m$ is the mass of the oscillator and $r$ is the damping constant. If the ratio $\frac{r ^{2}}{mk}$ is $8%$ , the change in time period compared to the undamped oscillator is approximately as follows:

Options:

Answer:

A

Solution:

The change in time period compared to the undamped oscillator increases by $1%$ .

TestHub · Accepted Answer

The change in time period compared to the undamped oscillator increases by 1% .

Physics - EMI/AC Question with Solution | TestHub

Options:

Doubts & Discussion