Physics - EMI/AC Question with Solution | TestHub

As the angle between field and plane is${60}^o$, therefore angle between area vector and magnetic field is,

$\theta ={30}^o$

Magnetic flux through the strip is

$\varphi =BA\mathit{cos}\theta$

$10^{-3}=B\left(0.02\right)\mathit{cos}30^o$

$B=\frac{10^{-3}}{\left(0.02\right)\left(\frac{\sqrt{3}}{2}\right)}$

$B=0.058 \mathrm{T}$