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PhysicsEMI/ACSeries AC CircuitsMedium2 minPYQ_2013

PhysicsMediumsingle choice

A coil of self-inductance $L$ is connected in series with a bulb $B$ and an $A C$ source. Brightness of the bulb decreases whenNEET 2013 (All India)

Answer:

Solution:

As $Z = R^{2} + X_{L}^{2} = R^{2} + (2 π f V L)^{2}$ As $/ = \frac{V}{Z}, P = /^{2} R$ i.e., $V ↑, L ↑\Rightarrow Z ↑, / ↓$ and $P ↓$

Stream:NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2013

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