Physics - EMI/AC Question with Solution | TestHub

Capacitive Reactance $\begin{array}{rl}{X}_C& =\frac{1}{\omega C}=\frac{1}{2\pi fC}=\frac{1}{2\times 3.14\times 50\times 10\times 10^{-6}}\\ & =\frac{1000}{3.14}\end{array}$ $\begin{array}{rl}& V_{\mathrm{rms}}=210\mathrm{V}\\ & i_{\mathrm{rms}}=\frac{V_{\mathrm{rms}}}{X_C}=\frac{210}{X_C}\end{array}$ $\begin{array}{rl}\text{ Peak current }& =\sqrt{2}{i}_{\mathrm{ms}}=\sqrt{2}\times \frac{210}{1000}\times 3.14=0.932\\ & \simeq 0.93\mathrm{A}\end{array}$