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PhysicsEMI/ACSeries AC CircuitsMedium2 minQB

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In the given circuit, $r m s$ value of current $(I_{r m s})$ through the resistor $R$ is :

Answer:

Solution:

Impedance of the given LCR circuit will be, $Z = R^{2} + (X_{L} - X_{C})^{2} \Rightarrow Z = 10 0^{2} + (200 - 100)^{2}$

$= 1002 Ω$

Therefore, RMS current can be written as,

$I_{r m s} = \frac{V _{r m s}}{Z} = \frac{200 2}{100 2}$

$= 2 A$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: QB

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