A 110 V , 50 Hz , AC source is connected in the circuit (as shown in figure). The current through the resistance 55 Ω , at resonance in the circuit, will be _____ A .

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Let current in the inductance is i L , through the capacitor is i C and through resistance is i R at any instance as shown in the figure. According to the Kirchoff's junction law, i R = i L + i C . At resonance X C = X L hence i L = i C . Also, current through the capacitor and inductor have phase difference of π rad . Therefore, they will form destructive interference and hence the current through the resistance will be 0 .

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