The magnetic field of a plane electromagnetic wave is B = 3 × 1 0 − 8 sin [ 200 π ( y + c t )] i ^ T, where c = 3 × 1 0 8 m s − 1 is the speed of light. The corresponding electric field is:

E 0 = c B 0 = 3 × 1 0 8 × 3 × 1 0 − 8 = 9 V/m Propagation direction ( E × B ) ∥ c : B ^ = i ^ c ^ = − j ^ E ^ = − k ^ E = − 9 sin [ 200 π ( y + c t )] k ^ V/m

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PhysicsEM WavesElectromagnetic wavesMedium3 minQB

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The magnetic field of a plane electromagnetic wave is $B = 3 \times 1 0^{- 8} sin [200 π (y + c t)] \hat{i}$ T, where $c = 3 \times 1 0^{8} m s^{- 1}$ is the speed of light. The corresponding electric field is:

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Answer:

Solution:

$E_{0} = c B_{0} = 3 \times 1 0^{8} \times 3 \times 1 0^{- 8} = 9$ V/m
Propagation direction $(E \times B) ∥ c$ :
$\hat{B} = \hat{i}$
$\overset{c}{^} = - \hat{j}$
$\hat{E} = - \hat{k}$
$E = - 9 sin [200 π (y + c t)] \hat{k}$ V/m

Subject:PhysicsTopic:EM WavesSubtopic:Electromagnetic waves

⏱ 3mℹ️ Source: QB

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