The electric field of a plane electromagnetic wave is given by E → = E 0 i ^ cos ⁡ k z c o s ⁡ ( ω t ) The corresponding magnetic field B → is then given by:

E → = E 0 i ^ c o s k z c o s ω t E → = E 0 2 i ^ c o s k z - ω t + E 0 2 i ^ c o s k z + ω t B → = E 0 2 C j ^ c o s k z - ω t + E 0 2 C j ^ c o s k z + ω t = E 0 2 C j ^ 2 s i n k z s i n ω t = E 0 C j ^ s i n k z s i n ω t

Physics - EM Waves Question with Solution | TestHub

PhysicsEM WavesElectromagnetic wavesMedium2 minPYQ_2019

PhysicsMediumsingle choice

The electric field of a plane electromagnetic wave is given by
$\vec{E} = E_{0} \hat{i} \cos (k z) c o s (ω t)$
The corresponding magnetic field $\vec{B}$ is then given by:

Options:

Answer:

Solution:

$\vec{E} = E_{0} \hat{i} c o s (k z) c o s (ω t)$
$\vec{E} = \frac{E_{0}}{2} \hat{i} c o s (k z - ω t) + \frac{E_{0}}{2} \hat{i} c o s (k z + ω t)$
$\vec{B} = \frac{E_{0}}{2 C} \hat{j} c o s (k z - ω t) + \frac{E_{0}}{2 C} \hat{j} c o s (k z + ω t)$
$= \frac{E_{0}}{2 C} \hat{j} [2 s i n (k z) s i n (ω t)]$
$= \frac{E_{0}}{C} \hat{j} [s i n (k z) s i n (ω t)]$

Stream:JEESubject:PhysicsTopic:EM WavesSubtopic:Electromagnetic waves

⏱ 2mℹ️ Source: PYQ_2019

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