For a plane electromagnetic wave, the magnetic field at a point $x$ and time $t$ is :
$\vec{B} (x, t) = [1 .2 \times 10^{- 7} \sin (0 .5 \times 10^{3} x + 1 .5 \times 10^{11} t) \hat{k}] T$ .
The instantaneous electric field $\vec{E}$ corresponding to $\vec{B}$ is :

Question

For a plane electromagnetic wave, the magnetic field at a point $x$ and time $t$ is :

$\vec{B} (x, t) = [1 .2 \times 10^{- 7} \sin (0 .5 \times 10^{3} x + 1 .5 \times 10^{11} t) \hat{k}] T$ .

The instantaneous electric field $\vec{E}$ corresponding to $\vec{B}$ is :

TestHub · Accepted Answer

E 0 = B 0 × C = 1 . 2 × 10 - 7 × 3 × 10 8 = 36 As the light is propagating in x direction. & E ^ × B ^ | | C ^ ∴ E → should be in j ^ direction. So electric field E → = E 0 sin E → · ( x , t ) = - 36 sin 0 . 5 × 10 3 x + 1 . 5 × 10 11 t j ^ V m

Physics - EM Waves Question with Solution | TestHub

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