Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsMedium2 minQB

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Two conducting spheres of radii $R$ and $3 R$ carry charges $Q$ and $- 2 Q$ . Between these spheres a neutral conducting sphere of radius $2 R$ is connected. The separation between the sphere is considerably large then :-

Options:

Answer:

A, B, D

Solution:

Finally potential on all sphere will be equal

$\frac{K Q _{1}}{R} = \frac{K Q _{2}}{2 R} = \frac{K Q _{3}}{3 R} and Q_{1} + Q_{2} + Q_{3} = (Q) + (- 2 Q) = - Q \Rightarrow Q_{1} = \frac{- Q}{6}, Q_{2} = \frac{- Q}{3}, Q_{3} = \frac{- Q}{2}$

Stream:JEESubject:PhysicsTopic:Electrostatics

⏱ 2mℹ️ Source: QB

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