Home
PYQ PracticeFree
JEE Rank Predictor
Answer Key

Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceHard2 minPYQ_2021

PhysicsHardsingle choice

Figure shows a rod $A B$ , which is bent in a $120 °$ circular arc of radius $R$ . A charge $(- Q)$ is uniformly distributed over rod $AB$ . What is the electric filed $\vec{E}$ at the centre of curvature $O$ ?

Question diagram: Figure shows a rod A B , which is bent in a 120 ° circular a

Options:

Answer:

A

Solution:

$δ = \frac{2 k λ}{R} \sin \frac{θ}{2} \hat{i}$

$= \frac{2 k}{R} (\frac{Q}{2 R \frac{π}{3}}) \sin 60 ° \hat{i}$

$= \frac{3 k Q}{π R^{2}} \frac{\sqrt{3}}{2} \hat{i}$

$= \frac{3 \sqrt{3}}{2 π} \frac{kQ}{R^{2}} \hat{i}$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...